Year 8 - Pythagoras' theorem - Free practice

Year 8 Pythagoras' Theorem Worksheets

Find the hypotenuse, find a shorter side, apply to word problems.

Quick answer

How do you use Pythagoras' theorem to find a missing side of a right-angled triangle?

Pythagoras' theorem states that in a right-angled triangle, the square of the hypotenuse equals the sum of the squares of the other two sides: a2+b2=c2a^2 + b^2 = c^2, where cc is the hypotenuse. To find a missing side, substitute the known sides and solve. For example, if a=3a = 3 and b=4b = 4, then c=9+16=5c = \sqrt{9 + 16} = 5.

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Six questions across Foundation, Standard and Extension, with full worked solutions, written to the Australian Curriculum.

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Worked examples

Year 8 pythagoras' theorem: worked examples

Three examples, from a standard question to a worded problem. Have a go at each one before you open the solution.

  1. Example 1 · Finding the hypotenuse

    A right-angled triangle has shorter sides of length 99 m and 1212 m. Find the length of the hypotenuse.

    Show worked solution

    Key idea: In a right-angled triangle, c2=a2+b2c^2 = a^2 + b^2, where cc is the hypotenuse.

    1. Substitute the known sides: c2=92+122c^2 = 9^2 + 12^2
    2. Evaluate: c2=81+144=225c^2 = 81 + 144 = 225
    3. Take the square root: c=225=15c = \sqrt{225} = 15

    Answer: The hypotenuse is 1515 m.

  2. Example 2 · Finding a shorter side

    A right-angled triangle has a hypotenuse of 1010 m and one shorter side of 66 m. Find the exact length of the other shorter side, then round your answer to two decimal places.

    Show worked solution

    Key idea: Rearrange a2+b2=c2a^2 + b^2 = c^2 to find a shorter side: b2=c2−a2b^2 = c^2 - a^2.

    1. Substitute the known values: b2=102−62b^2 = 10^2 - 6^2
    2. Evaluate: b2=100−36=64b^2 = 100 - 36 = 64
    3. Take the square root: b=64=8b = \sqrt{64} = 8
    4. The exact answer is 88 m, which rounds to 8.008.00 m.

    Answer: The other shorter side is exactly 88 m (or 8.008.00 m to two decimal places).

  3. Example 3 · Ladder reaching a wall

    A ladder is leaning against a vertical wall. The base of the ladder is 1.51.5 m from the wall along flat ground, and the ladder reaches 3.63.6 m up the wall. Find the length of the ladder, correct to two decimal places.

    Show worked solution

    Key idea: The ladder, wall, and ground form a right-angled triangle. The ladder is the hypotenuse.

    1. Substitute into c2=a2+b2c^2 = a^2 + b^2: c2=1.52+3.62c^2 = 1.5^2 + 3.6^2
    2. Evaluate: c2=2.25+12.96=15.21c^2 = 2.25 + 12.96 = 15.21
    3. Take the square root: c=15.21≈3.90c = \sqrt{15.21} \approx 3.90

    Answer: The ladder is approximately 3.903.90 m long.

Common mistakes

Where students usually lose marks

Adding instead of subtracting when finding a shorter side

Student writes b2=102+62=136b^2 = 10^2 + 6^2 = 136, even though the hypotenuse is known.

When finding a shorter side, subtract the square of the known shorter side from the square of the hypotenuse: b2=c2−a2b^2 = c^2 - a^2. Only add when finding the hypotenuse.

Choosing the wrong side as the hypotenuse

Student uses the longest given side as aa or bb rather than as cc.

The hypotenuse is always the side opposite the right angle, and it is always the longest side. Label cc first, then assign aa and bb to the other two sides.

Forgetting to take the square root

Student writes c2=225c^2 = 225 and gives the answer as 225225 m.

After finding c2c^2, always take the positive square root to get the length: c=225=15c = \sqrt{225} = 15.

Rounding √(b²) when b is a whole number

Student writes 64≈8.00\sqrt{64} \approx 8.00 and concludes the answer is not exact.

Check whether the square root is a whole number before rounding. If b2=64b^2 = 64, then b=8b = 8 exactly, and no rounding is needed (or the rounded form is simply 8.008.00).

Try one yourself

Your turn

A ladder leans against a wall. The base of the ladder is 1.81.8 m from the wall and the ladder reaches 2.42.4 m up the wall. How long is the ladder, correct to 2 decimal places? Give your answer in metres.

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About this worksheet

Why we built it

Pythagoras' theorem is one of the most-tested Year 8 topics. These worksheets give your student practice across the three standard question types - finding the hypotenuse, finding a shorter side, and applying Pythagoras to real-world problems like ladders, ramps and TV screen sizes.

What's covered

Sub-skills your student will practise

  • ✓Finding the hypotenuse given two shorter sides
  • ✓Finding a shorter side given the hypotenuse
  • ✓Identifying when a triangle is right-angled from its side lengths
  • ✓Applied problems (ladders, ramps, diagonal distances)
  • ✓Exact (surd) vs decimal answers

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Frequently asked

Questions parents ask about pythagoras' theorem

What is Pythagoras' theorem in plain English?

In a right-angled triangle, the square of the longest side (the hypotenuse) equals the sum of the squares of the other two sides. Written as a^2 + b^2 = c^2 where c is the hypotenuse.

How do students find a shorter side, not the hypotenuse?

Rearrange the formula: if c^2 = a^2 + b^2, then a^2 = c^2 - b^2. The shorter side equals the square root of the difference of squares, not the sum.

When does Pythagoras work?

Only in right-angled triangles. If the triangle has no 90-degree angle, Pythagoras doesn't apply - you'd need trigonometry or the cosine rule (Year 9-10 topics).

What real-world problems use Pythagoras?

Ladder problems (how tall a wall can a ladder reach), TV screen sizes (diagonal measurement), ramp gradients, and the distance between two points on a map. Year 8 introduces these contexts so the abstract formula has somewhere to land.

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